rubyonrailsin

You can do it like this:

# this array is just my representation of your data
paths = [["Root", "child A", "child A1"],

         ["Root", "child A"],
         ["Root", "child B", "child B999", "child C245"],
         ["Root", "child D", "child B41"],

         ["Root", "child A", "child Axyz"]]

# you can do the grouping like this
groups = paths.group_by{ |p| p[1] }

puts groups.inspect # this is a hash

/Lasse

2010/3/26 tom <tomabroad@gmail.com>

hi & thx 4 ur time:

x = find.almost_all
<p>
<% for y in @x.ancestors.reverse %>

  <%= link_to h(y.title), y  %> &gt;
<% end %>
</p>

results in:


Root > child A > child A1
Root > child A >
Root > child B > child B999 > child C245
Root > child D > child B41
Root > child A > child Axyz
....
....
..

how can i group the list above lets say by the second level, eg like this:

CHILD A
Root > child A > child A1
Root > child A >
Root > child A > child Axyz

CHILD B
Root > child B > child B999 > child C245

CHILD D
Root > child D > child B41


or even by length after grouping by title (CHILD A):
Root > child A >
Root > child A > child A1
Root > child A > child Axyz

 

On Fri, Mar 26, 2010 at 1:37 PM, Lasse Bunk <lassebunk@gmail.com> wrote:

Tom,

Maybe it's just me but I don't quite understand... Could you explain what you're trying to achieve?

/Lasse

2010/3/24 tom <tomabroad@gmail.com>

hi,

im using acts_as_tree and im not sure on how to group find-result.

x = find.almost_all

<p>
<% for y in @x.ancestors.reverse %>
  <%= link_to h(y.title), page  %> &gt;
<% end %>
</p>

gives me a nice "breadcrum". but how is it possible to group the list lets say by the 1level or second level?

thx

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